Multiple Choice
Given an isosceles triangle with equal side lengths $a = 5$ and base $b = 4$, what is the area of the triangle using the formula Area $= \frac{b\sqrt{4a^2 - b^2}}{4}$?
Calculate the area of an isosceles triangle with sides $a = 3$ and base $b = 4$ using the formula $= \frac{b\sqrt{4a^2 - b^2}}{4}$.
For an isosceles triangle with equal sides of length $a = 10$ and base $b = 6$, find the area using the formula Area $= \frac{b\sqrt{4a^2 - b^2}}{4}$.
If an isosceles triangle has sides $a = 7$ and base $b = 2$, what is its area using the formula $= \frac{b\sqrt{4a^2 - b^2}}{4}$?
An isosceles triangle has equal side lengths $a = 6$ and base $b = 8$. What is the area using the formula $= \frac{b\sqrt{4a^2 - b^2}}{4}$?
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