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The value of $x$ in $BD = x$ is calculated as $x = \frac{c^2 + a^2 - ^2}{2a}$.
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The perimeter of the triangle is , which is used to find the semi-perimeter.
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To find $AD^2$ from $\triangle ABD$, $AD^2 = c^2 - x^2$ where $x = \frac{c^2 + a^2 - b^2}{.
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For a triangle with sides $a$, $b$, and $c$, the semi-perimeter $s$ is calculated as $s = \frac{a + b + c}{}$.
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In Heron's formula, the expression under the square root sign is $s(s - a)(s - b)(s - )$.
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